A bit complicated. A 2F 2.7V capacitor can store Q=CV=5.4 Coulombs of charge. Now 1 mAh is 0.001 Columbs per second (0.001A) multiplied by 3600 seconds or 3.6 Coulombs. So I think the capacitor is equivalent to 5.4/3.6 = 1.5mAh. tai pagal analogija cia kaip 375 mah akumuliatorius {{:arduino:pasted:20181118-112841.png}}